16^(2x)=3x+1

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Solution for 16^(2x)=3x+1 equation:



16^(2x)=3x+1
We move all terms to the left:
16^(2x)-(3x+1)=0
We get rid of parentheses
16^2x-3x-1=0
We add all the numbers together, and all the variables
-3x+16^2x-1=0
We move all terms containing x to the left, all other terms to the right
-3x+16^2x=1

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